Typescript get class by name The class name works well using this. 0. Implications include not being able to call the base class accessor from the derived accessor. e. and also change the style of another di Input and output are diff in this way: I want type safety, example in the future if a field name changes, I will get a red line everywhere that field is used, if I use something Transaction. Using constructor. Commented Aug 2, 2021 at 17:58 Get name of function in typescript. class GenericListRenderer<T> { items: T[]; I'd like to get class name without instance. substring(Math. g Getting the class name of an Enum in Typescript. And I can access to the values in this ways obj['par1'] is it possible to do the same thing in TypeScript with a class like this: export class obj{ par1:string; par2:string; } this. (Pseudocode, doesn't work): class Foo { bar() { console. Does GDScript provide a way of getting the current class (node) name as a string? This would be useful for diagnostic messages, e. : print("%s: xxxxx" % classname) Share Sort by: Best TypeScript is a language for application-scale JavaScript development. name Property. what to use as the result of an arbitrary string lookup). TypeScript doesn't know that your keys have a special meaning in the context of the object so it is most likely not able to infer that the result of the lookup might be a function. Use the constructor property of the class. Usage, as per the TypeScript documentation : To get the runtime property names, you can use Object. for example: file1. Required, but never shown What is the most effective way to get an array of all class names for an element in Playwright using TypeScript? I cannot seem to find any API for this very typical task and had to write the following: As far as I know it is not possible to get the name of TResult, but if you provide the accordingly constructor function you can get the name. this[methodName as 'method1' | 'method2'] Or if you have some interface named for example Methods where all the methods you are going to call for this are declared. This property returns the Obtaining a class name at runtime in TypeScript. Improve this answer. Share Typescript now has the ConstructorParameters builtin, similar to the Parameters builtin. So the first thing we need to do is in your example is make A & B different somehow, so that Typescript can know the difference. You are asking for a way to get the name of the calling public method to pass to the method that does the logic so you don't have to actually type out all the public convenience methods. Reading property names from a class in TypeScript? 1. Get method name from within a typescript method. ts const How extract interface from exist class in typescript. ). export class workbookEntity { public name: string; public creationDate: string; constructor() { this. constructor. The instance of the class will come in the getter /setter function as this. Is it currently possible to implement an indexer on a class in TypeScript? class MyCollection { [name: string]: MyType; } This doesn't compile. I have the code below to find elements with their class name: // Get the element by their class name var cur_columns = document. querySelectorAll("[class*=page]") You can put the static methods in a base class, and then when you extend it the subclass will have those static methods as well: class Base { public static getGetters This ability to access and utilize the class name allows developers to perform tasks such as dynamic type checking, implementing conditional behaviors based on the object’s class, or organizing and categorizing objects based on their class affiliation. It simplifies code maintenance and promotes modularity by providing a standardized approach Although, with that said, I'm not sure you can note behaviour as part of the function interface. If you declare it with const you will find that it works. Angular 8 - How to query DOM elements by their attributes? 10. long. How to iterate through HTMLElements with specific class in TypeScript? thats the only way i found to get the class name by type input if you don't have a instance of an object. 3. Take the following example: function Daddy() {}; function Me() {}; Me. The only option I see is to make Animal class abstract and declare an abstract field name, but still it will class Awesome<ObjType extends Object Thanks, I found a solution to get class member's type in typescript type MEMBER_OF<TObject extends Object, TKey extends keyof TObject> = TObject[TKey} – cyrilluce. I have tested this in FF3 and IE7, I can't speak for other implementations. If you want to get the class name using a function, you can use the following extended version of classOf</code> that is originally from “JavaScript: The Definitive Guide”:</p> I don't think this is possible, because Function. Reason for the underscore Nice answer. Get class name using jQuery. They use it in the official documentation. All Functions have a name property. foo = "bar"; // setting foo to bar True named parameters don't exist in JavaScript nor in TypeScript but you can use destructuring to simulate named parameters: interface Names { name1: boolean name2: boolean name3: boolean name4: boolean } function myFunction({name1, name2, name3, name4}: Names) { // name1, etc. document. Add. To return only the property name, it might be feasible to return only the part of name after the last dot, using m[1]. Once unsuspended, idmontie will be able to comment and publish posts again. keys() to create the array, you get TypeScript to recognize that FooKeys has the type ("fizz" | "buzz")[]. name and class. name); } } However, I want to create a function and or class that inherits this ability and uses it to insert that class name into the URL. bar. If the functions are called 16 times per class than the original, non-typescript friendly method wins but the 2nd method, an object of named functions, is not that much slower, ~10% and of course if the functions did more than just an Get class name . name ()); // エラー :human. Modified 3 years, I'm adding a workaround I'm using to get the class parameter type for 2 classes that have nothing in common (it can be extended to cover more classes just by adding additional conditional). Decorators are invoked on with the class as the target not an instance of the the class. cookie is "FirstName=John" and you call getCookie("Name"), you'll get back "John" even though there's no cookie by that name. This is not a runtime question, but a typing question. So in your example -> class A { } and class B { } are the same Type. max call is used to handle the case when lastIndexOf would return -1, in which case the entire TypeScript 构造函数用于初始化对象的属性。它是一个可以参数化的特殊函数，如上例所示。有了 Animal 类，就可以从中创建对象。TypeScript 使用 new 关键字从给定的类创建新对象。由于 TypeScript 是一种强类型语言，新的 Animal 实例的类型将是 Animal 类型。 These code examples demonstrate different techniques to retrieve the class name of an object at runtime in TypeScript. In both cases, this is contingent on the value matching a publicly accessible property name of the given object’s type. T is just for compiler not for code. TypeScript 有一个配置项strictPropertyInitialization，只要打开，就会检查属性是否设置了初值，如果没有就报错。. You can for example rename them when importing them (e. Calling a typescript function named in a variable. A common question that crops up from time to time on TypeScript forums is how to check the type of a class at runtime using TypeScript. You can also use the Object. getElementsByClassName('className') would always return multiple elements because conceptually Classes are meant to be applied to multiple elements. name = 'my work book name'; this. 28. First is to use document. Then you get the name of that key using the reversed enum type. If you want to use get and set accessors, you have to prefix the private property with underscore. Thus, to access the class name statically, do in . Ask Question Asked 6 years, 6 months ago. 1. obj['par1']=value1 Update. constructor); I get undefined. typescript; Share. log(ApiBase. newItemFoo, – Ziagl. You can get the properties of an instance of an Object. TypeScript - get type of generic class parameter. Modified 7 years, 7 months ago. I have a function that is called mockDatabaseMethodByName that takes a db method name and the return value. name. e. You could have a look here. If you want only the first element in the DOM with that class, you can select the first element out of the array-like HTMLCollection returned. Is there a built-in (better) way other than looking up the type in the prototype of the class? class MyClass { private delegate: typeof MyClass. Here's an example: How to retrive the class name from caller prototype. 4. myMethod; // gets the type ( boolean ) => number; public myMethod( arg: boolean ) { return 3. It's currently marked as "Awaiting More Feedback", so if you need this functionality you might Seems you don't understand generics. log(this. this[methodName Sometimes, a TypeScript developer may need to find the class name of an object. ; Add a class constant with the name. One way to get the class name in TypeScript is by utilizing the constructor. Now i have edited my code. Get name of calling property in TypeScript. me. I want to get all interfaces names from a specific file. ES6 classes are mostly just syntactical sugar to ES5. log(fnc. console. ts private interface first{ } private interface second{ } private interface third{ } file2. concat(q(rule. Get TypeScript enum name from instance. TypeScript 构造函数用于初始化对象的属性。它是一个可以参数化的特殊函数，如上例所示。有了 Animal 类，就可以从中创建对象。TypeScript 使用 new 关键字从给定的类创建新对象。由于 TypeScript 是一种强类型语言， If anyone's looking for a TypeScript version of MarsRobot's answer, try this: function nameof<T>(obj: T, expression: (x: { [Property in keyof T]: => string How to get Generic class<T> name of typescript? 1. lastIndexOf(". At the TypeScript level, if you wanted to declare a variable that could contain the keys for an instance of your class, you'd do it like this: let s: keyof typeof myClass; Example on One common way to get the class name from an instance in TypeScript is by using the instanceof operator. rules || rule. For more information on Index types and the keyof keyword, check out the Typescript documentation. getPrototypeOf(), the constructor property, or even custom properties. How to get the type of a property by name using generics. Method 1: Using typeof and constructor class MyClass { // } const myObject = new MyClass(); const className = typeof myObject. The property key name is passed into the handler methods, and so you can actually get the behavior you're looking for: const c = new C(); c. Although you can get a reference to the function that's on B. Thanks. obj["bar"]. log(MyClass. Add Answer . In derived class you will get the name of that class, not MyNode. The Math. name to get the class name, which in this case is "Person". 6. There are two possible solution. I would like to be able to get the class or file name from the annotation. In JavaScript, this doesn't work: typeof obj return "object" or something else, but never the name of the class. are boolean } I'm writing a function that operates on an object by key name, but it should only allow keys with specific values. – TypeScript 在运行时获取对象的类名在本文中，我们将介绍如何在TypeScript中在运行时获取对象的类名。在进行问题解决之前，我们先来了解一下TypeScript的类和对象的概念。阅读更多：TypeScript 教程 TypeScript 类和对象 TypeScript是一种静态类型的编程语言，它是JavaScript的超集，为JavaScript提供了更大的可 Use extends to create class inheritance in Typescript. name }`; } } class B Let's say I have: class Foo {} class Bar extends Foo {} var clazz = Bar; I figured out that to get Bar there's clazz. If I only have a generic parameter at hand (for example in a generic class), there is no way to create a runtime instance of it's instanciated type or use the name of the instanciated type, even if the typescript class decorator: typing properties defined in decorator function. We don’t get a lot of information using typeof in JavaScript or TypeScript. You can set them when running npm script in following way: env NG_BUILD_MANGLE=false NG_BUILD_MINIFY=false NG_BUILD_BEAUTIFY=true ng build --prod This will result in unminified output, yet tree When I try to get property names from a class, getOwnPropertyNames returns only properties with values. Live collections Also it would be great if I could use that class in TypeScript to access the static members; in other words, name: string; } abstract class A { toString(): string { return `class: ${ (Object. The index signature hide mapping of any other members. Currently it is impossible to convert between function parameter names or tuple element labels and string literal types. This can be done, although a little differently to other languages. Viewed 1k times In typescript how do you retrieve Class name from within the Class itself? For example, given the following code: export class SomeRandomName extends AbstractSomething<SomeType> implements One common way to get the class name from an instance in TypeScript is by using the instanceof operator. And then you can just override it in your derived. Say we have class Test: class Test { I'm trying to get the name of a class at runtime (minified!) in a class decorator. sonClassName'), otherwise it will handle it as sonClassName is a tag name not a class name – Hamza Dahmoun Commented Apr 16, 2020 at 15:29 I am using typescript annotations at method level. Other answers mainly get all name of object, to get value of property, you can use yourObj[name], for example: Basically class name is under property name of its object if you are referencing constructor. log(directionName); // 'North' Getting All Enum Names. I have module like this. Commented Jan 29 Thanks for the tips, it should work as I confirm it on Typescript playground, but the same into my project give me an "Object" class name I edit my question to add these details, but maybe it's the beginning of a new problem Nice answer. g. However, I used the following method to do it: Now, all of your objects will have the function, getName(), that will return the name of the constructor as a string. This doesn't mean you I have a class where I have the constructor defined with 3 parameters which are all optional. However it is different in a few regards. Here's the deal. Note: There are new annoucement published on 25th August with TypeScript 4. Is there any way to get derived class name?? – Swarna Latha. It works but I want the return value to be inferred based on the method name. Maximilian Steiger answered on November 8, 2021 Popularity 10/10 Helpfulness 5/10 Contents ; answer typescript get class name; related typescript get class properties; More Related Answers ; c# get class name by type; How to get the Class Name of an Object in JavaScript; export class ApiBase { constructor() { const instance = new ApiBase(); console. Instead of using a variable in obj[x], you can write:. getPrototypeOf() method to get the class name, like this: typescript class Animal {} class Dog extends Animal {} const dog = new Dog(); console. Follow answered Apr 5, 2016 at 13:14. This only makes sense, if the context of the caller is non-generic, which might often not be the case. If you have an instance of a class, you can use the name of the constructor function to This is really a question about JavaScript semantics, not TypeScript specifically. Your helper must ignore all Function properties (= class methods). Here’s the TypeScript type that extracts all properties of a class and creates a new type for them: I'd like to have the property names of this interface in an array like this: try defining it as a class. 467. Whether you’re making minor style adjustments or working with more complex DOM manipulation scenarios, TypeScript’s Is there a way to get the method/function name in a TypeScript class? The following TypeScript code aims to print the class name and the method name during runtime. Get Angular component class from DOM element. There is a feature request at microsoft/TypeScript#44939 asking to support type-level manipulations of function parameter names and tuple labels. If carService is defined as an object literal, it will lack an index signature (i. I want to get the property names of a simple Typescript object. What you can do, is what's shown in this answer—wrap referencing the property in a function, convert the function to a string, then extract the property name out of the string. foo; // getting foo c. Angular cli builder supports NG_BUILD_MANGLE, NG_BUILD_MINIFY, NG_BUILD_BEAUTIFY node environment params (checked in version 8). It can be a class which implements some interface or extends some abstract class. Whereas HTMLCollection has two methods, NodeList has five methods, including NodeList. namespace] and at runtime you have an instance of the GuidGenerator, how do you get the full class name including module name, in this case: “research. if you want to map methods inside a class, you need to add "this" for example: Foo: this. I used this example from the TypeScript wiki How to get Generic class<T> name of typescript? 1. name, but how do I get the method name? export class MyClass { public myMethod() { console. log(ctor. But it does not work well. keys method to get a list of all the static variable and method names attached to a class. In typescript you can use a class like an interface. This operator checks if an object is an instance of a specific class or constructor function. querySelectorAll() instead, which uses CSS selectors. It can be generic because for each of my frontend entities (User, Group, ) there is an endpoint "/api/user", "/api/group", so I can use the following method with success. This is the Documents class I just tried this code with a very simple case, and it worked, but there's something that doesn't make sense to me. Is there any way to get the Type by it's type name? I have a class: class Foo{} I have another class: class Bar(){ constructor(){ const typeName = "Foo" Type<any> type = Type. getPrototypeOf(dog). This doesn't mean you I want to get the name of the current method from within an instance method of a class in Typescript. Name. (You could assign a property to B with the name, though. name) //Prints out SomeClass return <any>null; } One thing to note here is, interfaces are enforced types at compile-time, while objects are mostly run-time. Add a class constant with the name. name return the class name in proper ES6. 1. Typescript - create interface from list of With the keyof keyword we can cast a given value to an Index type or set a variable to the property name an object. bo, there's no link from there back to B. I can specify an indexer on an interface, of course, but I need methods on this type as well as the indexer, so an interface won't suffice. const a = { prop1: Name. name variable is of type string, TypeScript doesn't make this function of string literal type for every particular function or class. uid instead of a string directly. name)} //this is throwing error} } class Cow extends Animal{ constructor(){ super() } } new Cow() // this should log "Cow" In angular 6, I have a typescript class like this. By understanding how to use type assertions and type guards, developers can create flexible, type-safe web applications. 7. 14; } } So as it turns out, you can just use the Object. someFn. For example I have this class: To get the name of an instance method without any magic strings, and in a way that is re-factorable, you can use the following: SomeClass. I'm looking to get the name of method that belongs to a class and store it in a variable in TypeScript / JavaScript. prototype = new Daddy; me = new Me;. If you want to get the class name using a function, you can use the following extended version of classOf that is originally from “JavaScript: The Definitive Guide”:</p> You can if you map all your interfaces to their name, like below. I just swallowed the pill and switched to Babel; Traceur's development seems to be somewhat stagnant, and many ES6 features are poorly implemented. name); // returns "Test" Share. Here's a function to do that: How to get Generic class<T> name of typescript? Share. Nope, there's nothing built into the language that allows you to get the name of an enum at runtime. So it'd be nice to express that through the type system. The getElementsByClassName() method is a versatile tool for selecting and manipulating DOM elements in TypeScript. Declaration: execute<TResult>(ctor: { new (): TResult }) : <TResult> { console. I don't want to just use a switch clause like this: Node. keys({ obj })[0] Getting the class name of an Enum in Typescript. typeof does not return the class name - it's behaviour is well documented on MDN. Get all classes/constructors by given @decorators. I am writing an internal layer b/w database and models. All static properties are inherited by the class, this also works for subclassing as well, we actually get a real prototype link between a subclass constructor function and the Answer. I wrote the following code: interf Anyway the proxy implements a get handler and a set handler and so it intercepts all gets and sets for all properties. /long-class-name";). When you implement "get bar()" in a derived class, you are replacing "get bar()" in the parent. I have code setup as: class Animal{ constructor(){ console. Retrieve Typescript class properties. constructor is a Function. name); // i want it display test her Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company If mock every method I have the type info available but as soon as I create a function wrapper, things start to get messy. max(0, m[1]. Get list of attribute decorators in TypeScript. creationDate = '2018/01/26'; } } And let's say I want to get the names and values of the variables of an instance of this class in another class' function: How do I get the name of an object's type in JavaScript? Get an object's class name at runtime in TypeScript. How can I add and remove class by getElementBy id in angular 8. sort The only reason to use a variable here is to choose an arbitrary property from your IFoo interface. Please be aware of it. forEach, which can be used to iterate through a NodeList. prototype. Improve this question. This can be useful for various scenarios such as debugging, logging, or even for conditional operations based on class names. getOwnPropertyNames. function getProperty<T, K extends keyof T>(o: T, name: K) { return o[name]; } Of course, one can get the type of the property by replacing return o[name] into return typeof o[name]. log(x. How can i get the name of the sub class (which is invoking the constructor of base class) from base class itself in TypeScript. getOwnPropert Because I cannot comment to the answer of Titian Cernicova-Dragomir:. So, you could say that you have a sorter interface that takes two values and returns a number, but function multiply(a, b) { return a * b } also matches that signature, yet it isn't fit for sorting. call(this, value); } Sorry. log(className); // Output: "function". This property returns the name of the constructor function that created the object. (written in ES2017) dot notation also works fine. clear(); class A{ test(){ } testCall(fnc:Function){ console. Follow answered May 29, 2017 at 9:16. Handy, but there's another caveat: if your object has a prototype chain (aside from Object), you will get the the name of the first link in that chain, not the name of the constructor used to create the object. At most, it tells us whether a value is undefined, number, string, or object. At most, it tells us whether a value is undefined , number , string , or object . GuidGenerator”. getElementsByClassName('column'); // Now remove them for (var i = 0 I'd like to create a generic TypeScript class for rendering (as a HTML list) of an array of objects which implement a specific interface. GetType(). Share. 2. In this blog post, we will explore how to get the class name in TypeScript. TypeScript is a typed superset of JavaScript that compiles to plain @user3132564 tried to edit this in, but its actually a comment: This method returns the wrong value when you search for a suffix of a cookie - if the value of document. Typescript: object with classes as a values. Required, but never shown Post Your Answer I would like to iterate a TypeScript enum object and get each enumerated symbol name, for example: enum myEnum { entry1, entry2 } for (var entry in myEnum) { // use entry's name here, e. class Derived extends Base { . This is why using an arrow function is a bad idea here, as they capture this from declaration site. log(className); // Output: "MyClass" I couldn't be getting plain text in return if I'm explicitly calling a method that searches for Elements by their class name. log('Class name: ' + this. Name. Classes/modules don't necessarily have a unique name across your application. cssRules)); looks like it expects something to be returned from the q function, but that function has no return value. TypeScript: Get member name of const enum as a string? 0. getElementsBy* methods return a live HTMLCollection, not a NodeList, getElementsByName being an exception. One simple way to get the class name in Typescript is by accessing the constructor. TypeScript can extract properties from a class type and create a new type of it. ????); // Should output "MyClass" This guide has explored different ways to retrieve the class name of an instance at runtime in TypeScript. In all other cases don't use it. This won't work: foo=func(Response) func getName(obj) { return Object. getElementsByClassName() call. They will in ES6, but they don't yet. export class Hello { id: number; name?:string; txt?:string; } From a component controller, I would like to retrieve an array with the property names, without needing to create an object. log(instance. 664. Right now there's not really a great way of doing this, but there are currently some open suggestions on github (See #1579, #394, and #1003). If object is an instance of some class, you need to get its constructor and then get a name. There really isn't a good way to do that: in order for the class to be well-typed you'll need to spell out the methods, and once you do that it isn't any more typing to add the explicit As @Domenic says, use someClassInstance. Follow answered Feb 8, 2022 at 10:32. Eg. Ask Question Asked 8 years, 3 months ago. name); console. Improve this As stated in the documentation of TypeScript about the keyof operator, one can get a property of an object instance using the function below. my. From basic examples to more advanced scenarios, each has its place To achieve this, TypeScript offers multiple approaches, including using the instanceof operator, Object. Ask Question Asked 9 years, 3 months ago. How do I retrieve the name of Failing that, you can look to querySelector and a substring matching attribute selector:. interface Blueberry { strawberry: boolean; } interface Car { vehicle: number; } interface Interfaces { Blueberry: Blueberry; Car: Car; } thats the only way i found to get the class name by type input if you don't have a instance of an object. It's currently marked as "Awaiting More Feedback", so if you need this functionality you might I have the following code but I have to repeat the interface properties in the class otherwise I get: Class incorrectly implements interface. name property of an object. log(Test. mtizziani I'm looking for a way to get an object property name with typechecking that allows to catch possible regressions after refactoring. Did you mean to use it without '()'? An up-to-date answer in 2021. I'm guessing that the real work is done by accumulating values in ret, but you would be accumulating You prevent the duplication, but only if you drop the index signature from CurrentPages. name); Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company The challenge is to get the type name from the type after it's been passed into a function. name; console. log (human. If you have some class or method which is doing the same for any input (and it is able to do it), and you want compiler to validate output. name) //Prints out SomeClass return <any>null; } Usage: execute<SomeClass>(SomeClass); The name of the class will be related to the variable - eg. Get enum values by enum name string. For arbitrary strings, you either have to check and cast, or use an index signature, but the former is probably preferable for this case. Parameters Official Doc Just make a method called methodToBeCalled in your base that acts like a dummy, other languages have something called abstract methods, and this would be pretty similiar. I was hoping to be able to pass in named parameters so I don't need to pass in undefined. Seen as your using Typescript, interface's might even be a better fit, but you might be best explaining what problem your trying to solve. Solution with template string will certainly not work, because they exist only in TS 4. Let’s assume we have the class [GuidGenerator] in a TypeScript module [research. How do I retrieve the name of I have a class with properties (like name, date,) class Product { name: string date: Date } What I expect is to get a list of properties with type : [{field: "name", type: "string"}, {field: "date", type: "Date"}] Edit : I want to do that because I'm creating a scaffold tool to create with CLI a new object. I would say using underscore with accessors is a special case and although it's not explicitly written in Coding guidelines, it doesn't mean it's wrong. getMetadata('design:type', target. But you have to add the dot next to the class name querySelector('. Get property class instance in property decorator. As per Tim Perry's link, TypeScript has now added keyof, which is a great feature for getting the available properties of a class. log(className); // Output: "MyClass" If I'm not mistaken, for properties of objects this will return the class qualified name, for example: Foo. That function returns elements which have all of the classes specified in the first argument as a space-separated string. Not used Getting Class Name in TypeScript inside an export function from a special parameter. – Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company 上面示例中，属性x和y的类型都会被推断为 number。. Here is my test code. You must create yourself a helper type that extracts all properties from a class type. class MyClass {} const instance = new MyClass(); const className = instance. So, TL;DR, the following piece of code should satisfy the needs: The general answer to the question is "no". namespace. log(Object. We then create an instance of the Person class and use constructor. How to retrieve property names for all properties in a class in typescript excluding methods. constructor We don’t get a lot of information using typeof in JavaScript or TypeScript. Is there a way to get ALL properties, and not just the ones with values? class Klass { How to retrieve property names for all properties in a class in typescript excluding methods. So, it's not like the function interface solves your type problems. we need strings for database calls but want to pass keyName in a way it can be auto typescript get class name. ; This article analyses both solutions and shows how to code them with real-life TypeScript examples. module System { export module Collections { export class MyClass{ } } } than in another module i will create instance of MyClass This results in you passing the name of the class as a parameter, which should provide the name: let myName = getName(MyClass); The downside is that you cannot do this to just a generic that is derived from the type of a data value. name No, you can't achieve that with only one document. And there can be multiple classes with the same name. NET, it's easy to get the class name of an object using obj. log(something); //what TypeScript offers special syntax for turning a constructor parameter into a class property with the same name and value. If you want to get the class name using a function, you can use the following extended version of classOf that is originally from “JavaScript: The Your first problem is that you have to remember Typescript types are based on the Shape of an interface, there not Hard Types. GetType(typeName) //like C# } } I want to get the type of Foo by it's name holding in a string I have a class with properties (like name, date,) class Product { name: string date: Date } What I expect is to get a list of properties with type : [{field: "name", type: "string"}, {field: "date", type: "Date"}] Edit : I want to do that because I'm creating a scaffold tool to create with CLI a new object. I want to remove class 'col-md-12' and add 'col-md-6' when the user click the details icon. 5). 8. querySelectorAll("[class^=page]") but that will only work if pageSomething is the first listed class name in the class attribute. Say I have a class Class A {} TypeScript class do not exist at run time as it is transpiled down to plain old JavaScript. var elements = Can anyone help with how to find 'All' Elements with a particular class name in Angular 2? How to get all elements by class name in Angular 8 from the typescript file. This article analyses both solutions and shows how to code them with in . "))). Typescript get object property type from name. I would like to dynamically assign multiple properties to MyClass in TypeScript so there is no need to write multiple lines of code for setting class properties. Also, note that, unlike in C#, properties are not currently virtualized in TypeScript (v0. 8. @Esteban mentions in the comments that . As you mentioned, instance. Ask Question Asked 3 years, 8 months ago. constructor as AConstructor). const some = (arg: string) => { return (target: any, propertyKey: Getting the class name of an Enum in Typescript. typeof The typeof operator returns a string Sometimes, a TypeScript developer may need to find the class name of an object. So for your example, define/generate your class like this: instead of Object. 3 1 1 bronze badge. Here's a relevant StackOverflow page which answers this question and, as with all things JavaScript, points out some of the gotchas. The Node object corresponding to the class definition has a decorators array but I can't find a way to get the name of each decorator. keys(Hello); // ["id", "name", "txt"] Is that possible ? To obtain the name of a specific enum entry, you can access it like so: let directionName: string = Direction[Direction. To get the names of all enum entries, you can use the Object. These techniques allow developers to determine One straightforward way to get the class name of an object in TypeScript is by utilizing the constructor. I have a generic service which saves data into a remote backend. The code ret. I'm trying to get the type of an instance method of a class. How can I find out what is the parent class of Bar? I was looking for a way to get name of function passing in parameter console. To find the class name of an object at runtime in TypeScript, you can:. That's because the type is now the literal "text" and you can access the property text. There are remarkable differencences between these two lists. TypeScript source parsing: Get class decorator names. (As @derek mentioned in another answer, the common denominator of interface and object can be a class that serves both a type and a value. Using a regular function work best in this case. – Matthieu Riegler. js & Typescript: Define Class in Sandbox, then use it outside. type BaseCore<T extends Record<string, PageCtor>> = { [key in keyof T]?: Hi there I am new in typescript and i'd like to ask if it is possible get full name of class include module names . Make sure you pass the class type, not the instance: ConstructorParameters<typeof SomeClass> ConstructorParameter Official Doc. TypeScript class decorator get class name. Luckily, it is easy to do. North]; console. For example. It works perfectly with autocomplete on the value string and everything. name property. Something like: ObjectType. import { LongClassName as LCN } from ". constructor; // Output: "function" console. AdmiralUrun AdmiralUrun. name is not a function This expression is not callable because it is a 'get' accessor. Modified 8 years, 3 months ago. Then you are having generic functionality. To get an object’s class name at runtime with TypeScript, we canm use the name property of the constructor or class. This property returns the name of the constructor If you want to get the class name using a function, you can use the following extended version of classOf that is originally from “JavaScript: The Definitive Guide”: To find the class name of an object at runtime in TypeScript, you can: Use the constructor property of the class. How to get the type definition name of an object? 1. When I do this: const metadata = Reflect. 14. class User { id!:number; name!:string } //It should use object type. keys() method by first converting the enum to an object: Get Class Name in Typescript. 1,773 1 1 gold badge 9 9 silver badges 13 13 bronze badges. 9. You can't*, for a couple of reasons: Functions don't have a name property. You can then use the InstanceType conditional type to get the instance type from a class type:. Get Typescript interface property type, given property name only. Modified 4 years, 6 months ago. This property returns the name of the constructor Is there a way to get properties names of class in TypeScript? In the example, I would like to 'describe' the class A or any class and get an array of its properties (maybe only public ones?), is it . passing 'Two' will create ClassTwo. export class Simple { myProperty: string; otherProperty: string = "some text"; } var s = new Simple(); Object. getPrototypeOf(this). keys or Object. lukbl lukbl. – M - Commented Jun 23, Get the type of a nested class in TypeScript. 如果你打开了这个设置，但是某些情况下，不是在声明 As far as I know it is not possible to get the name of TResult, but if you provide the accordingly constructor function you can get the name. You seem to only have one. Is it possible to get an object's class/type name at runtime using TypeScript? class MyClass{} var instance = new MyClass(); console. The linkage is one-way. These are called parameter properties and are created by prefixing a One simple way to get the class name in Typescript is by accessing the constructor. Second - to access base class you can use super keyword: public Add(value: any) { super. For instance, we write class MyClass {} const x = new MyClass(); console. I just left to put extends. Get property names of object. name then unexpectedly returns 'Daddy', not 'Me'. Required, but never shown Post Your You have to use type assertion to tell the compiler that methodName value is restricted so it can only be one of the method names which are declared for this. Email. Take a look at the following setup: class Foo { bar(){ // logic } } In this blog post, we will explore different ways to get the class name in Typescript. That's not the reason. . someClassInstance. When using an interface, is there a TypeScript shorthand for doing this without having to declare Id: number; and all the other properties in the class? 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Typescript get class by name. You could have a look here.